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7x^2-45x+12=0
a = 7; b = -45; c = +12;
Δ = b2-4ac
Δ = -452-4·7·12
Δ = 1689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-\sqrt{1689}}{2*7}=\frac{45-\sqrt{1689}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+\sqrt{1689}}{2*7}=\frac{45+\sqrt{1689}}{14} $
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